Dave has an amazing summation: $\displaystyle \sum_{n=1}^\infty \frac{n^{13}}{e^{2\pi n} - 1} = \frac{1}{24}$
Moreover, this is exactly equal to the integral!
$\displaystyle \int_0^\infty \frac{x^{13}}{e^{2 \pi x} - 1} dx = \displaystyle \sum_{n=1}^\infty \frac{n^{13}}{e^{2\pi n} - 1} = \frac{1}{24}$
Published: Nov 4, 2022 @ 18:15.
Last Modified: Apr 28, 2023 @ 08:59.
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