Volume in Conical Tank at t = 5 min

A photo of a whiteboard titled: Volume in Conical Tank at t = 5 min

We find the height of water in a conical tank such that:

$$ V = \frac{1}{3} \pi x^3 $$

given that water is flowing in at a rate $dV/dt = 1 m^3 / min$.

Meta